4x^2+72x=252

Solution for 4x^2+72x=252 equation:

4x^2+72x=252

We move all terms to the left:

4x^2+72x-(252)=0

a = 4; b = 72; c = -252;
Δ = b2-4ac
Δ = 722-4·4·(-252)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-96}{2*4}=\frac{-168}{8}
=-21
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+96}{2*4}=\frac{24}{8}
=3
$